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Common exam pitfall
Students often swap DIV and MOD, returning the remainder for DIV and the quotient for MOD.
In computer science, integer arithmetic frequently requires decomposing divisions into two distinct components: the whole number of times a divisor fits into a dividend, and the leftover remainder.
1. The Distinction Between /, DIV, and MOD
Operator | Full Name | Purpose | Example ( |
|---|---|---|---|
| Real Division | Divides and returns a floating-point |
|
| Integer Division | Returns the integer quotient, discarding any fractional remainder. |
|
| Modulo Division | Returns the remainder left over after integer division. |
|
Fundamental Mathematical Identity:
2. Common Exam Applications in Cambridge Paper 2
1. Unit & Time Conversions
Transforming flat units (e.g. seconds, cents, grams) into compound units (e.g. hours/minutes/seconds, dollars/cents, kilograms/grams):
Hours <- TotalSeconds DIV 3600
RemainingSeconds <- TotalSeconds MOD 3600
Minutes <- RemainingSeconds DIV 60
Seconds <- RemainingSeconds MOD 602. Odd and Even Number Determination
Any integer N is even if and only if dividing by 2 leaves zero remainder:
IF Number MOD 2 = 0 THEN
OUTPUT "Number is Even"
ELSE
OUTPUT "Number is Odd"
ENDIF3. Extracting and Stripping Digits
- Extract units digit:
Units <- Value MOD 10(e.g.247 MOD 10 = 7) - Strip units digit:
Value <- Value DIV 10(e.g.247 DIV 10 = 24)
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Exam-Style Check: Distinguish DIV and MOD Operations
• Multiple ChoiceWhat are the evaluated results of 29 DIV 6 and 29 MOD 6 in Cambridge pseudocode?
Interactive exercises for Module 2 and beyond require an active plan.